expm1

expm1, expm1f, expm1l - exponential minus 1

#include <math.h>
 I double expm1(double  x );

I float expm1f(float  x );

I long double expm1l(long double  x );
 

Link with -lm.

I expm1( x ) returns a value equivalent to `exp (x) - 1'. It is computed in a way that is accurate even if the value of x is near zeroa case where `exp (x) - 1' would be inaccurate due to subtraction of two numbers that are nearly equal.

BSD, C99. The float and long double variants are C99 requirements.

exp(3), log(3), log1p(3)